We will find both x- and y-intercepts extremely useful when drawing the graph of
Example 10. Place the quadratic function y = x2 +2x−24 in vertex form. Plot
the vertex and axis of symmetry and label them with their coordinates and
respectively. Find and plot the x- and y-intercepts of the parabola and label
The graph is a parabola that opens upward; it is shifted 1 unit to the left and
downward. This information is enough to plot and label the vertex, then plot and
the axis of symmetry, as shown in Figure 5(a).
To find the x-intercepts, let y = 0 in y = x2 + 2x − 24.
0 = x2 + 2x − 24
The leading coefficient is a 1. The integer pair −4 and 6
has product −24 and sum 2.
Thus, the right-hand side factors as fol lows .
Recall that we let y = 0. We’ve found two solutions , x = −6 and x = 4. Thus, we
x-intercepts at (−6, 0) and (4, 0), as pictured in Figure 5(b).
Finally, to find the y-intercept, let x = 0 in y = x2+2x−24. With this
y = −24. Thus, the y-intercept is (0,−24), as pictured in Figure 5(c). Note that
also included the mirror image of the y-intercept across the axis of symmetry.
(a) Plotting the vertex
and axis of symmetry.
(b) Adding the x-intercepts
provides added accuracy.
(c) Adding the
y-intercept and its
mirror image provides
an excellent final graph.
The graph of this last equation is a parabola that opens
downward, translated 7/4 units
to the left and 169/8 units upward. This is enough information to plot and label
vertex and axis of symmetry, as shown in Figure 6(a).
To find the y-intercepts, set f(x) = 0 in f(x) = −2x2 − 7x + 15. We will also
multiply both sides of the resulting equation by −1.
0 = −2x2 − 7x + 15
0 = 2x2 + 7x − 15
After comparing 2x2 +7x−15 with ax2 +bx+c, we note that the integer pair −3 and
10 have product equal to ac = −30 and sum equal to b = 7. Use this pair to
the middle term of 2x2 + 7x − 15 as a sum and then factor by grouping .
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