2. When n = 47, the algorithm would check if the numbers
2, 3, 4, 5, and 6 (round
down √47 to the nearest integer) are divisors of 47.
N one of these integers divide 47, and the algorithm would de termine that 47 is
prime and return 0.
3. When n = 209 a quick computation shows that the
algorithm would check the
integers 2, 3, 4, …, 14 in order to find any possible divisors. When it checks
the algorithm will find that 11 does divide 209 and return the number 11.
40. 2010 can represent a number in decimal (the regular number 2,010) or
hexadecimal (this would represent the decimal number 8,208), but not in binary
(the latter does not allow for a 2)
41. 1101010 can represent a number in binary, decimal and hexadecimal.
56. See the back of the book.
57. Use the explanation in example 5.2.15 as an example.
If n = 15 we trace through the algorithm updating result = result*x every time n
odd. We update x to be x*x every time we execute a loop.
x Current value of n N mod 2 Result = result*x New n
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